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/*******************************************************************************
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 * Copyright (c) 2005, 2010 IBM Corporation and others.
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 * All rights reserved. This program and the accompanying materials
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 * are made available under the terms of the Eclipse Public License v1.0
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 * which accompanies this distribution, and is available at
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 * http://www.eclipse.org/legal/epl-v10.html
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 *
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 * Contributors:
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 *     IBM Corporation - initial API and implementation
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 *     Alexander Shatalin (Borland) - Contribution for Bug 238874
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 *******************************************************************************/
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package org.eclipse.draw2d.geometry;
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/**
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 * A Utilities class for geometry operations.
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 * 
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 * @author Pratik Shah
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 * @author Alexander Nyssen
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 * @since 3.1
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 */
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public class Geometry {
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	/**
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	 * Determines whether the two line segments p1->p2 and p3->p4, given by
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	 * p1=(x1, y1), p2=(x2,y2), p3=(x3,y3), p4=(x4,y4) intersect. Two line
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	 * segments are regarded to be intersecting in case they share at least one
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	 * common point, i.e if one of the two line segments starts or ends on the
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	 * other line segment or the line segments are collinear and overlapping,
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	 * then they are as well considered to be intersecting.
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	 * 
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	 * @param x1
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	 *            x coordinate of starting point of line segment 1
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	 * @param y1
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	 *            y coordinate of starting point of line segment 1
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	 * @param x2
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	 *            x coordinate of ending point of line segment 1
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	 * @param y2
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	 *            y coordinate of ending point of line segment 1
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	 * @param x3
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	 *            x coordinate of the starting point of line segment 2
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	 * @param y3
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	 *            y coordinate of the starting point of line segment 2
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	 * @param x4
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	 *            x coordinate of the ending point of line segment 2
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	 * @param y4
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	 *            y coordinate of the ending point of line segment 2
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	 * 
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	 * @return <code>true</code> if the two line segments formed by the given
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	 *         coordinates share at least one common point.
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	 * 
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	 * @since 3.1
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	 */
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	public static boolean linesIntersect(int x1, int y1, int x2, int y2,
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			int x3, int y3, int x4, int y4) {
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		// calculate bounding box of segment p1->p2
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		int bb1_x = Math.min(x1, x2);
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		int bb1_y = Math.min(y1, y2);
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		int bb2_x = Math.max(x1, x2);
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		int bb2_y = Math.max(y1, y2);
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		// calculate bounding box of segment p3->p4
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		int bb3_x = Math.min(x3, x4);
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		int bb3_y = Math.min(y3, y4);
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		int bb4_x = Math.max(x3, x4);
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		int bb4_y = Math.max(y3, y4);
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		// check if bounding boxes intersect
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		if (!(bb2_x >= bb3_x && bb4_x >= bb1_x && bb2_y >= bb3_y && bb4_y >= bb1_y)) {
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			// if bounding boxes do not intersect, line segments cannot
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			// intersect either
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			return false;
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		}
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		// If p3->p4 is inside the triangle p1-p2-p3, then check whether the
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		// line p1->p2 crosses the line p3->p4.
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		long p1p3_x = (long) x1 - x3;
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		long p1p3_y = (long) y1 - y3;
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		long p2p3_x = (long) x2 - x3;
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		long p2p3_y = (long) y2 - y3;
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		long p3p4_x = (long) x3 - x4;
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		long p3p4_y = (long) y3 - y4;
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		if (productSign(crossProduct(p2p3_x, p2p3_y, p3p4_x, p3p4_y),
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				crossProduct(p3p4_x, p3p4_y, p1p3_x, p1p3_y)) >= 0) {
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			long p2p1_x = (long) x2 - x1;
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			long p2p1_y = (long) y2 - y1;
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			long p1p4_x = (long) x1 - x4;
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			long p1p4_y = (long) y1 - y4;
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			return productSign(crossProduct(-p1p3_x, -p1p3_y, p2p1_x, p2p1_y),
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					crossProduct(p2p1_x, p2p1_y, p1p4_x, p1p4_y)) <= 0;
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		}
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		return false;
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	}
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	private static int productSign(long x, long y) {
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		if (x == 0 || y == 0) {
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			return 0;
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		} else if (x < 0 ^ y < 0) {
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			return -1;
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		}
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		return 1;
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	}
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	private static long crossProduct(long x1, long y1, long x2, long y2) {
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		return x1 * y2 - x2 * y1;
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	}
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	/**
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	 * @see PointList#polylineContainsPoint(int, int, int)
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	 * @since 3.5
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	 */
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	public static boolean polylineContainsPoint(PointList points, int x, int y,
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			int tolerance) {
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		int coordinates[] = points.toIntArray();
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		/*
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		 * For each segment of PolyLine calling isSegmentPoint
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		 */
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		for (int index = 0; index < coordinates.length - 3; index += 2) {
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			if (segmentContainsPoint(coordinates[index],
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					coordinates[index + 1], coordinates[index + 2],
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					coordinates[index + 3], x, y, tolerance)) {
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				return true;
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			}
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		}
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		return false;
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	}
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	/**
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	 * @return true if the least distance between point (px,py) and segment
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	 *         (x1,y1) - (x2,y2) is less then specified tolerance
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	 */
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	private static boolean segmentContainsPoint(int x1, int y1, int x2, int y2,
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			int px, int py, int tolerance) {
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		/*
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		 * Point should be located inside Rectangle(x1 -+ tolerance, y1 -+
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		 * tolerance, x2 +- tolerance, y2 +- tolerance)
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		 */
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		Rectangle lineBounds = Rectangle.SINGLETON;
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		lineBounds.setSize(0, 0);
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		lineBounds.setLocation(x1, y1);
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		lineBounds.union(x2, y2);
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		lineBounds.expand(tolerance, tolerance);
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		if (!lineBounds.contains(px, py)) {
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			return false;
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		}
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		/*
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		 * If this is horizontal, vertical line or dot then the distance between
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		 * specified point and segment is not more then tolerance (due to the
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		 * lineBounds check above)
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		 */
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		if (x1 == x2 || y1 == y2) {
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			return true;
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		}
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		/*
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		 * Calculating square distance from specified point to this segment
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		 * using formula for Dot product of two vectors.
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		 */
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		long v1x = x2 - x1;
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		long v1y = y2 - y1;
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		long v2x = px - x1;
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		long v2y = py - y1;
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		long numerator = v2x * v1y - v1x * v2y;
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		long denominator = v1x * v1x + v1y * v1y;
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		long squareDistance = numerator * numerator / denominator;
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		return squareDistance <= tolerance * tolerance;
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	}
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	/**
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	 * One simple way of finding whether the point is inside or outside a simple
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	 * polygon is to test how many times a ray starting from the point
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	 * intersects the edges of the polygon. If the point in question is not on
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	 * the boundary of the polygon, the number of intersections is an even
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	 * number if the point is outside, and it is odd if inside.
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	 * 
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	 * @see PointList#polygonContainsPoint(int, int)
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	 * @since 3.5
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	 */
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	public static boolean polygonContainsPoint(PointList points, int x, int y) {
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		boolean isOdd = false;
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		int coordinates[] = points.toIntArray();
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		int n = coordinates.length;
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		if (n > 3) { // If there are at least 2 Points (4 ints)
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			int x1, y1;
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			int x0 = coordinates[n - 2];
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			int y0 = coordinates[n - 1];
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			for (int i = 0; i < n; x0 = x1, y0 = y1) {
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				x1 = coordinates[i++];
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				y1 = coordinates[i++];
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				if (!segmentContaintPoint(y0, y1, y)) {
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					// Current edge has no intersection with the point by Y
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					// coordinates
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					continue;
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				}
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				int crossProduct = crossProduct(x1, y1, x0, y0, x, y);
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				if (crossProduct == 0) {
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					// cross product == 0 only if this point is on the line
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					// containing selected edge
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					if (segmentContaintPoint(x0, x1, x)) {
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						// This point is on the edge
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						return true;
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					}
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					// This point is outside the edge - simply skipping possible
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					// intersection (no parity changes)
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				} else if ((y0 <= y && y < y1 && crossProduct > 0)
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						|| (y1 <= y && y < y0 && crossProduct < 0)) {
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					// has intersection
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					isOdd = !isOdd;
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				}
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			}
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			return isOdd;
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		}
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		return false;
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	}
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	/**
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	 * @return true if segment with two ends x0, x1 contains point x
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	 */
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	private static boolean segmentContaintPoint(int x0, int x1, int x) {
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		return !((x < x0 && x < x1) || (x > x0 && x > x1));
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	}
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	/**
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	 * Calculating cross product of two vectors: 1. [ax - cx, ay - cx] 2. [bx -
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	 * cx, by - cy]
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	 */
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	private static int crossProduct(int ax, int ay, int bx, int by, int cx,
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			int cy) {
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		return (ax - cx) * (by - cy) - (ay - cy) * (bx - cx);
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	}
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}
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